This is similar to my previous post on the property correlation of a fluid to use it in calculations making results better & life simpler.
This time I am putting the formula for calculating the Kinematic Viscosity of air vs temperature.
The correlation is as below.
kv = -1.1555 x 10^(-14) x T^3 9.5728 x 10^(-11) x T^2 + 3.7604 x 10^(-8) x T - 3.4484 x 10^(-6)
Where
kv is kinematic viscosity in M2/sec
T is in K
The above equation is valid from T = 100 to 1600 K.
This time I am putting the formula for calculating the Kinematic Viscosity of air vs temperature.
The correlation is as below.
kv = -1.1555 x 10^(-14) x T^3 9.5728 x 10^(-11) x T^2 + 3.7604 x 10^(-8) x T - 3.4484 x 10^(-6)
Where
kv is kinematic viscosity in M2/sec
T is in K
The above equation is valid from T = 100 to 1600 K.
6 comments:
is it + or - between T^3 and 9.5728....
kv = -1.1555 x 10^(-14) x T^3 9
There's a symbol missing from your formula . would you suppose I should stick in "+" or "-" between the "3" and the "9" at end of the portion I've clipped? Thanks, Dave.
-3.4007469023437027e-06 T^0
+3.4521387370766878e-08 T^1
+1.0088177790668354e-10 T^2
-1.3635276379481259e-14 T^3
T in kelvin, kinematic viscosity in square meter per second.
I'd use this equation if this link is correct:
http://www.engineeringtoolbox.com/air-absolute-kinematic-viscosity-d_601.html
Dave
Yes Dear, I missed it. Its + sign between "T ^3" & "9".
Thanks for identifying the short fall.
Hi, would anyone know where I can find such a correlation but with the temperature as well with the barometric pressure or altitude effect taken into account to determine the proper dynamic viscosity.
Hugo
I just used this equation in matlab and it gave 1.5679*10^-5 for T = 295. This is off by about 20% I'd reckon. Don't use this formula.
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